What is the solution for y^'=8*(2+y)/x ,y(1)=8 ?

The solution for y^'=8*(2+y)/x ,y(1)=8 is y=10x^8-2

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y^'=8*(2+y)/x ,y(1)=8

y^{^{'}} = 8 \cdot \frac{2 + y}{x}, y (1) = 8

y = 10 x^{8} - 2

Solution steps

y^{'} (x) = 8 \cdot \frac{2 + y}{x}

Solve separable ODE:

y = 10 x^{8} - 2

y = 10 x^{8} - 2

y = 6 cot (3 x)

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What is the solution for y^'=8*(2+y)/x ,y(1)=8 ?
The solution for y^'=8*(2+y)/x ,y(1)=8 is y=10x^8-2