What is (\partial ^2)/(\partial y^2)((xy)/(x-y)) ?

The answer to (\partial ^2)/(\partial y^2)((xy)/(x-y)) is (2x^2)/((x-y)^3)

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(\partial ^2)/(\partial y^2)((xy)/(x-y))

\frac{\partial ^{2}}{\partial y ^{2}} (\frac{x y}{x - y})

\frac{2 x ^{2}}{( x - y ) ^{3}}

Solution steps

\frac{\partial ^{2}}{\partial y ^{2}} (\frac{x y}{x - y})

\frac{\partial}{\partial y} (\frac{x y}{x - y}) = \frac{x ^{2}}{( x - y ) ^{2}}

= \frac{\partial}{\partial y} (\frac{x ^{2}}{( x - y ) ^{2}})

\frac{\partial}{\partial y} (\frac{x ^{2}}{( x - y ) ^{2}}) = \frac{2 x ^{2}}{( x - y ) ^{3}}

= \frac{2 x ^{2}}{( x - y ) ^{3}}

\int \frac{3 + x}{1 - x ^{2}} d x

y = (5 - x^{2})^{5}

\int x^{2} + 6 x + 13 d x

f (x) = \frac{1}{x ^{3}}, at x = 1

\frac{\partial}{\partial x} (y^{6} sin (5 x))

What is (\partial ^2)/(\partial y^2)((xy)/(x-y)) ?
The answer to (\partial ^2)/(\partial y^2)((xy)/(x-y)) is (2x^2)/((x-y)^3)