What is (\partial)/(\partial x)(y^3-ln(x)) ?

The answer to (\partial)/(\partial x)(y^3-ln(x)) is -1/x

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(\partial)/(\partial x)(y^3-ln(x))

\frac{\partial}{\partial x} (y^{3} - ln (x))

- \frac{1}{x}

Solution steps

\frac{\partial}{\partial x} (y^{3} - ln (x))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{3}) - \frac{\partial}{\partial x} (ln (x))

\frac{\partial}{\partial x} (y^{3}) = 0

\frac{\partial}{\partial x} (ln (x)) = \frac{1}{x}

= 0 - \frac{1}{x}

Simplify

= - \frac{1}{x}

\int 4 x \cdot e^{x} d x

\frac{\partial}{\partial x} (- \frac{9 x}{y})

- x^{^{'}} - \frac{x}{0.00022} + 13364 = 0

\frac{d}{d x} (ln (\frac{x + 2}{x + 1}))

\int \frac{a + b x ^{8}}{9 a x + b x ^{9}} d x

What is (\partial)/(\partial x)(y^3-ln(x)) ?
The answer to (\partial)/(\partial x)(y^3-ln(x)) is -1/x