What is area y=-x-1,x=-1,x=2,y=0 ?

The answer to area y=-x-1,x=-1,x=2,y=0 is 9/2

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area y=-x-1,x=-1,x=2,y=0

area

y = - x - 1, x = - 1, x = 2, y = 0

\frac{9}{2}

Decimal Notation

4.5

Solution steps

Apply the area formula:

\int_{- 1}^{2} ∣ x + 1 ∣ d x

Solve

\int_{- 1}^{2} ∣ x + 1 ∣ d x : \frac{9}{2}

The area is:

= \frac{9}{2}

\int_{0}^{π} x^{2} sin (2 x) d x

\frac{d}{d x} (a x^{2} + b - 4)

\frac{2 s + 1}{s ^{3} + 7 s ^{2} + 12 s}

\frac{d}{d x} (cosh (0))

e^{x}, x^{2} - 1, x = - 1, x = 1

What is area y=-x-1,x=-1,x=2,y=0 ?
The answer to area y=-x-1,x=-1,x=2,y=0 is 9/2