What is (\partial)/(\partial x)(-x^2y) ?

The answer to (\partial)/(\partial x)(-x^2y) is -2xy

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(\partial)/(\partial x)(-x^2y)

\frac{\partial}{\partial x} (- x^{2} y)

- 2 x y

Solution steps

\frac{\partial}{\partial x} (- x^{2} y)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - y \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - y \cdot 2 x^{2 - 1}

Simplify

= - 2 x y

\frac{d}{d x} (sec (x) d x)

\int - sec^{3} (x) sin (x) d x

\int_{7}^{e^{4}} \frac{1}{x} d x

7 x - x^{2}, 2 x, 0, 5

\frac{2 t}{t ^{2} + 1}

What is (\partial)/(\partial x)(-x^2y) ?
The answer to (\partial)/(\partial x)(-x^2y) is -2xy