What is the derivative of 5/x+x-4 ?

The derivative of 5/x+x-4 is -5/(x^2)+1

What is the first derivative of 5/x+x-4 ?

The first derivative of 5/x+x-4 is -5/(x^2)+1

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Popular >

\frac{d}{d x} (\frac{5}{x} + x - 4)

- \frac{5}{x ^{2}} + 1

Solution steps

\frac{d}{d x} (\frac{5}{x} + x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{5}{x}) + \frac{d x}{d x} - \frac{d}{d x} (4)

\frac{d}{d x} (\frac{5}{x}) = - \frac{5}{x ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (4) = 0

= - \frac{5}{x ^{2}} + 1 - 0

Simplify

= - \frac{5}{x ^{2}} + 1

\frac{d}{d x} ((\frac{5 x + 1}{2 x}) d x)

\frac{\partial}{\partial t} (2 r sin (t))

\frac{d}{d x} (x^{3} - 9 x^{2} + 10 x)

\int 1 + cos (y) d y

\int \frac{3 x ^{2} + 4 x - 6}{x ^{2} + 16 x + 64} d x

What is the derivative of 5/x+x-4 ?
The derivative of 5/x+x-4 is -5/(x^2)+1
What is the first derivative of 5/x+x-4 ?
The first derivative of 5/x+x-4 is -5/(x^2)+1