What is the integral of sqrt(1-cos^2(x)) ?

The integral of sqrt(1-cos^2(x)) is -cos(x)+C

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integral of sqrt(1-cos^2(x))

\int 1 - cos^{2} (x) d x

- cos (x) + C

Solution steps

\int 1 - cos^{2} (x) d x

Rewrite using trig identities

= \int sin^{2} (x) d x

sin^{2} (x) = (sin (x)),

assuming

sin (x) \geq 0

= \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= - cos (x)

Add a constant to the solution

= - cos (x) + C

\frac{d}{d x} (- 4 x^{3} + 4 x)

x^{2}, (0, 3)

\int c (x) d x

h (x) = [\frac{x + 1}{x - 1}]^{3}

\frac{\partial}{\partial x} ((\frac{y}{z})^{\frac{1}{x}})

What is the integral of sqrt(1-cos^2(x)) ?
The integral of sqrt(1-cos^2(x)) is -cos(x)+C