What is (\partial)/(\partial x)(x+y+x^3+y^2) ?

The answer to (\partial)/(\partial x)(x+y+x^3+y^2) is 3x^2+1

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(\partial)/(\partial x)(x+y+x^3+y^2)

\frac{\partial}{\partial x} (x + y + x^{3} + y^{2})

3 x^{2} + 1

Solution steps

\frac{\partial}{\partial x} (x + y + x^{3} + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (x^{3}) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

\frac{\partial}{\partial x} (y^{2}) = 0

= 1 + 0 + 3 x^{2} + 0

Simplify

= 3 x^{2} + 1

y^{^{'}} = x^{2} (x - 2)^{2} (x - 1)^{2}

\int_{- 1}^{1} (3 x^{3} - x^{2} + x - 1) d x

x^{3} sin (7 x)

\frac{\partial}{\partial x} (sin (7 x + y + 3 z))

\frac{d}{d x} (6 + 7 x)

What is (\partial)/(\partial x)(x+y+x^3+y^2) ?
The answer to (\partial)/(\partial x)(x+y+x^3+y^2) is 3x^2+1