What is the derivative of-6sin(3x) ?

The derivative of-6sin(3x) is -18cos(3x)

What is the first derivative of-6sin(3x) ?

The first derivative of-6sin(3x) is -18cos(3x)

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\frac{d}{d x} (- 6 sin (3 x))

- 18 cos (3 x)

Solution steps

\frac{d}{d x} (- 6 sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 6 \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - 6 cos (3 x) \cdot 3

Simplify

= - 18 cos (3 x)

\int \frac{1}{cos ( x ) + 2 sin ( x ) + 3} d x

n = 2 \sum \infty \frac{ln ( n ^{2} )}{n}

\frac{( s ^{2} + 1 )}{s + 5}

\int_{0}^{4} (2 x + 4)^{- \frac{1}{2}} d x

\frac{\partial}{\partial y} (x sin (y) sin (z))

What is the derivative of-6sin(3x) ?
The derivative of-6sin(3x) is -18cos(3x)
What is the first derivative of-6sin(3x) ?
The first derivative of-6sin(3x) is -18cos(3x)