What is (\partial)/(\partial y)(xsin(y)sin(z)) ?

The answer to (\partial)/(\partial y)(xsin(y)sin(z)) is xsin(z)cos(y)

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(\partial)/(\partial y)(xsin(y)sin(z))

\frac{\partial}{\partial y} (x sin (y) sin (z))

x sin (z) cos (y)

Solution steps

\frac{\partial}{\partial y} (x sin (y) sin (z))

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x sin (z) \frac{\partial}{\partial y} (sin (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= x sin (z) cos (y)

\frac{d}{d x} (ln (\frac{x + 6}{x - 6}))

y^{^{'}} = - \frac{2 x y}{1 + x ^{2}}

f (z) = \frac{1}{z}

\int 25 t^{4} e^{- t^{5}} d t

x \to 13 lim (π)

What is (\partial)/(\partial y)(xsin(y)sin(z)) ?
The answer to (\partial)/(\partial y)(xsin(y)sin(z)) is xsin(z)cos(y)