What is the solution for (dy)/(dx)=(x-1)/(y-4) ?

The solution for (dy)/(dx)=(x-1)/(y-4) is y=4+sqrt(x^2-2x+c_{1)+16},y=4-sqrt(x^2-2x+c_{1)+16}

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(dy)/(dx)=(x-1)/(y-4)

\frac{d y}{d x} = \frac{x - 1}{y - 4}

y = 4 + x^{2} - 2 x + c_{1} + 16, y = 4 - x^{2} - 2 x + c_{1} + 16

Solution steps

\frac{d y}{d x} = \frac{x - 1}{y - 4}

Solve separable ODE:

y = 4 + x^{2} - 2 x + c_{1} + 16, y = 4 - x^{2} - 2 x + c_{1} + 16

y = 4 + x^{2} - 2 x + c_{1} + 16, y = 4 - x^{2} - 2 x + c_{1} + 16

\frac{d}{d x} (\frac{x - 4}{x})

n = 1 \sum \infty \frac{1}{4 n}

\frac{d}{d x} (x^{3} - \frac{3 x ^{2}}{2})

\int \frac{1}{20} x d x

y^{^{'}} = 2 y^{2} sin (x)

What is the solution for (dy)/(dx)=(x-1)/(y-4) ?
The solution for (dy)/(dx)=(x-1)/(y-4) is y=4+sqrt(x^2-2x+c_{1)+16},y=4-sqrt(x^2-2x+c_{1)+16}