What is (\partial)/(\partial y)(x/(3+y)) ?

The answer to (\partial)/(\partial y)(x/(3+y)) is -x/((3+y)^2)

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(\partial)/(\partial y)(x/(3+y))

\frac{\partial}{\partial y} (\frac{x}{3 + y})

- \frac{x}{( 3 + y ) ^{2}}

Solution steps

\frac{\partial}{\partial y} (\frac{x}{3 + y})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial y} (\frac{1}{3 + y})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= x \frac{\partial}{\partial y} ((3 + y)^{- 1})

Apply the chain rule:

- \frac{1}{( 3 + y ) ^{2}} \frac{\partial}{\partial y} (3 + y)

= - \frac{1}{( 3 + y ) ^{2}} \frac{\partial}{\partial y} (3 + y)

\frac{\partial}{\partial y} (3 + y) = 1

= x (- \frac{1}{( 3 + y ) ^{2}} \cdot 1)

Simplify

x (- \frac{1}{( 3 + y ) ^{2}} \cdot 1) : - \frac{x}{( 3 + y ) ^{2}}

= - \frac{x}{( 3 + y ) ^{2}}

\frac{\partial}{\partial t} (k e^{- \frac{t}{R ( t ) C}})

\frac{d}{d t} (8 t^{3})

\frac{d}{d x} (ln (x^{2} + x^{2} + 1))

\int \frac{1}{1 - 2 x ^{2}} d x

\frac{d}{d x} (x^{\frac{1}{3}} + 2 x)

What is (\partial)/(\partial y)(x/(3+y)) ?
The answer to (\partial)/(\partial y)(x/(3+y)) is -x/((3+y)^2)