What is the solution for (df)/(dx)+2f=fx^3 ?

The solution for (df)/(dx)+2f=fx^3 is f(x)=e^{(x^4)/4-2x+c_{1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(df)/(dx)+2f=fx^3

\frac{df}{d x} + 2 f = f x^{3}

f (x) = e^{\frac{x ^{4}}{4} - 2 x + c_{1}}

Solution steps

\frac{df}{d x} + 2 f = f x^{3}

Solve separable ODE:

f (x) = e^{\frac{x ^{4}}{4} - 2 x + c_{1}}

f (x) = e^{\frac{x ^{4}}{4} - 2 x + c_{1}}

\int_{5}^{6} \frac{1}{6 x - 1} d x

n = 0 \sum \infty (\frac{1}{3})^{n}

\int \frac{3 t ^{2} + 3}{t - 1} d t

2 x^{2} + 3, x, (- 1, 2)

\frac{d}{d x} (\frac{1}{1 + 5 x ^{2}})

What is the solution for (df)/(dx)+2f=fx^3 ?
The solution for (df)/(dx)+2f=fx^3 is f(x)=e^{(x^4)/4-2x+c_{1}}