What is the integral of (\sqrt[4]{x}) ?

The integral of (\sqrt[4]{x}) is 4/5 x^{5/4}+C

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integral of (\sqrt[4]{x})

\frac{4}{5} x^{\frac{5}{4}} + C

Solution steps

Apply the Power Rule

: \frac{4}{5} x^{\frac{5}{4}}

= \frac{4}{5} x^{\frac{5}{4}}

Add a constant to the solution

= \frac{4}{5} x^{\frac{5}{4}} + C

\frac{d x}{d y} + 3 x y^{3} = 0

3 y^{2} - 2 x^{2} = 6 - 2 x y, (3, 2)

y = x^{2} - 11, y = 10 x

\frac{d}{d x} (\frac{x - 3}{x + 3})

\int \frac{x ^{2}}{( - x + 1 ) ( x + 1 )} d x

What is the integral of (\sqrt[4]{x}) ?
The integral of (\sqrt[4]{x}) is 4/5 x^{5/4}+C