What is the solution for y(dy)/(dx)=x-1 ?

The solution for y(dy)/(dx)=x-1 is y=sqrt(x^2-2x+c_{1)},y=-sqrt(x^2-2x+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y(dy)/(dx)=x-1

y \frac{d y}{d x} = x - 1

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

Solution steps

y \frac{d y}{d x} = x - 1

Solve separable ODE:

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

\frac{1}{5 - 5 x ^{3}}

\int 19 e^{x} d x

x \to 1 lim (x^{2} - 1)

\int e^{x} sin (x) x d x

\frac{s}{s ( s ^{2} + s + 1 )}

What is the solution for y(dy)/(dx)=x-1 ?
The solution for y(dy)/(dx)=x-1 is y=sqrt(x^2-2x+c_{1)},y=-sqrt(x^2-2x+c_{1)}