What is (\partial)/(\partial x)((2x+1)^2) ?

The answer to (\partial)/(\partial x)((2x+1)^2) is 4(2x+1)

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(\partial)/(\partial x)((2x+1)^2)

\frac{\partial}{\partial x} ((2 x + 1)^{2})

4 (2 x + 1)

Solution steps

\frac{\partial}{\partial x} ((2 x + 1)^{2})

Apply the chain rule:

2 (2 x + 1) \frac{\partial}{\partial x} (2 x + 1)

= 2 (2 x + 1) \frac{\partial}{\partial x} (2 x + 1)

\frac{\partial}{\partial x} (2 x + 1) = 2

= 2 (2 x + 1) \cdot 2

Simplify

= 4 (2 x + 1)

\frac{d}{d x} (4 x^{2})

\frac{\partial}{\partial z} (e^{x})

\frac{d}{d x} (x^{2} 5 e^{x})

y^{3} - (6 x + 2) + 3 x y^{2} y^{^{'}} = 0

(x^{3} - 4 x)^{8}

What is (\partial)/(\partial x)((2x+1)^2) ?
The answer to (\partial)/(\partial x)((2x+1)^2) is 4(2x+1)