What is the first derivative of 4x^2 ?

The first derivative of 4x^2 is 8x

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derivative of 4x^2

\frac{d}{d x} (4 x^{2})

8 x

Solution steps

\frac{d}{d x} (4 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 \cdot 2 x^{2 - 1}

Simplify

= 8 x

\frac{\partial}{\partial z} (e^{x})

\frac{d}{d x} (x^{2} 5 e^{x})

y^{3} - (6 x + 2) + 3 x y^{2} y^{^{'}} = 0

(x^{3} - 4 x)^{8}

\int x cos^{2} (x) d x