What is the derivative of 9x^2-x^3 ?

The derivative of 9x^2-x^3 is 18x-3x^2

What is the first derivative of 9x^2-x^3 ?

The first derivative of 9x^2-x^3 is 18x-3x^2

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derivative of

9 x^{2} - x^{3}

18 x - 3 x^{2}

Solution steps

\frac{d}{d x} (9 x^{2} - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x^{2}) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (9 x^{2}) = 18 x

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 18 x - 3 x^{2}

\int x 4 x - x^{2} d x

\frac{d}{d x} (\frac{2 e ^{l n^{2} (x)} ln ( x )}{x})

y^{^{''}} - 6 y^{^{'}} + 3 y = 0

x \to 3 lim (\frac{x ^{2} - 9}{x - 3})

f (x) = \frac{( x ^{2} - 2 x - 48 )}{x + 6}

What is the derivative of 9x^2-x^3 ?
The derivative of 9x^2-x^3 is 18x-3x^2
What is the first derivative of 9x^2-x^3 ?
The first derivative of 9x^2-x^3 is 18x-3x^2