What is the solution for y^{''}-6y^'+3y=0 ?

The solution for y^{''}-6y^'+3y=0 is y=c_{1}e^{(3+sqrt(6))t}+c_{2}e^{(3-sqrt(6))t}

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y^{''}-6y^'+3y=0

y^{^{''}} - 6 y^{^{'}} + 3 y = 0

y = c_{1} e^{(3 + 6) t} + c_{2} e^{(3 - 6) t}

Solution steps

y^{''} (t) - 6 y^{'} (t) + 3 y = 0

Solve linear ODE:

y = c_{1} e^{(3 + 6) t} + c_{2} e^{(3 - 6) t}

y = c_{1} e^{(3 + 6) t} + c_{2} e^{(3 - 6) t}

x \to 3 lim (\frac{x ^{2} - 9}{x - 3})

f (x) = \frac{( x ^{2} - 2 x - 48 )}{x + 6}

2 x^{2} - 1

\int arctan (x + 1) d x

\int \frac{cos ( x )}{3 cos ( x ) - 5} d x

What is the solution for y^{''}-6y^'+3y=0 ?
The solution for y^{''}-6y^'+3y=0 is y=c_{1}e^{(3+sqrt(6))t}+c_{2}e^{(3-sqrt(6))t}