What is the solution for 100y^{''}-729y=0,y(0)=3,y^'(0)=1 ?

The solution for 100y^{''}-729y=0,y(0)=3,y^'(0)=1 is y=(3-71/54)e^{(27t)/(10)}+71/54 e^{-(27t)/(10)}

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100y^{''}-729y=0,y(0)=3,y^'(0)=1

100 y^{^{''}} - 729 y = 0, y (0) = 3, y^{^{'}} (0) = 1

y = (3 - \frac{71}{54}) e^{\frac{27 t}{10}} + \frac{71}{54} e^{- \frac{27 t}{10}}

Solution steps

100 y^{''} (t) - 729 y = 0

Solve linear ODE:

y = (3 - \frac{71}{54}) e^{\frac{27 t}{10}} + \frac{71}{54} e^{- \frac{27 t}{10}}

y = (3 - \frac{71}{54}) e^{\frac{27 t}{10}} + \frac{71}{54} e^{- \frac{27 t}{10}}

f (x) = \frac{1}{x}, at x = 4

x \to 5 + lim (\frac{x + 5}{x - 5})

\frac{d}{d x} (sin^{2} (\frac{1}{x}))

\int sin (x) e^{c o s (x)} d x

(4 x^{2} + 9)^{6}

What is the solution for 100y^{''}-729y=0,y(0)=3,y^'(0)=1 ?
The solution for 100y^{''}-729y=0,y(0)=3,y^'(0)=1 is y=(3-71/54)e^{(27t)/(10)}+71/54 e^{-(27t)/(10)}