What is the integral of 1/(ks) ?

The integral of 1/(ks) is 1/k ln|s|+C

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integral of 1/(ks)

\int \frac{1}{k s} d s

\frac{1}{k} ln ∣ s ∣ + C

Solution steps

\int \frac{1}{k s} d s

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{k} \cdot \int \frac{1}{s} d s

Use the common integral:

\int \frac{1}{s} d s = ln (∣ s ∣)

= \frac{1}{k} ln ∣ s ∣

Add a constant to the solution

= \frac{1}{k} ln ∣ s ∣ + C

\int \frac{1}{x ^{2} - 0.01} d x

\frac{d}{d x} (3 - \frac{1}{x})

\int \frac{x ^{3}}{1 + x} d x

y^{^{''}} - y^{^{'}} - 2 y = - 6 t + 4 t^{2}

y = sin (x), (4 π, 0)