What is the derivative of 5x^4-3x^2+7 ?

The derivative of 5x^4-3x^2+7 is 20x^3-6x

What is the first derivative of 5x^4-3x^2+7 ?

The first derivative of 5x^4-3x^2+7 is 20x^3-6x

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\frac{d}{d x} (5 x^{4} - 3 x^{2} + 7)

20 x^{3} - 6 x

Solution steps

\frac{d}{d x} (5 x^{4} - 3 x^{2} + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{4}) - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (7)

\frac{d}{d x} (5 x^{4}) = 20 x^{3}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (7) = 0

= 20 x^{3} - 6 x + 0

Simplify

= 20 x^{3} - 6 x

x \to \infty lim ((a)^{x})

\int \frac{1}{2 - 8 x} d x

y^{^{'}} + 3 x^{2} y = sin (x) e^{- x^{3}}, y (0) = 1

x^{3} b^{5} + y^{4} b + z^{6}

\int - sin (t) cos (t) d t

What is the derivative of 5x^4-3x^2+7 ?
The derivative of 5x^4-3x^2+7 is 20x^3-6x
What is the first derivative of 5x^4-3x^2+7 ?
The first derivative of 5x^4-3x^2+7 is 20x^3-6x