What is (\partial)/(\partial x)(1/(1+0^2)) ?

The answer to (\partial)/(\partial x)(1/(1+0^2)) is 0

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(\partial)/(\partial x)(1/(1+0^2))

\frac{\partial}{\partial x} (\frac{1}{1 + 0 ^{2}})

0

Solution steps

\frac{\partial}{\partial x} (\frac{1}{1 + 0 ^{2}})

\frac{1}{1 + 0 ^{2}} = 1

= \frac{\partial}{\partial x} (1)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

2 ln (cos (x))

- \frac{y}{2}

\frac{d}{d x} (tan^{2} (sin (x)) + cos (2 x))

f (x) = arctan (\frac{x}{2})

4 y^{^{''}} = y

What is (\partial)/(\partial x)(1/(1+0^2)) ?
The answer to (\partial)/(\partial x)(1/(1+0^2)) is 0