What is the derivative of ((x+1^2)/(3x-4)) ?

The derivative of ((x+1^2)/(3x-4)) is (3x^2-8x-11)/((3x-4)^2)

What is the first derivative of ((x+1^2)/(3x-4)) ?

The first derivative of ((x+1^2)/(3x-4)) is (3x^2-8x-11)/((3x-4)^2)

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\frac{d}{d x} (\frac{( x + 1 ) ^{2}}{3 x - 4})

\frac{3 x ^{2} - 8 x - 11}{( 3 x - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{( x + 1 ) ^{2}}{3 x - 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( ( x + 1 ) ^{2} ) ( 3 x - 4 ) - \frac{d}{d x} ( 3 x - 4 ) ( x + 1 ) ^{2}}{( 3 x - 4 ) ^{2}}

\frac{d}{d x} ((x + 1)^{2}) = 2 (x + 1)

\frac{d}{d x} (3 x - 4) = 3

= \frac{2 ( x + 1 ) ( 3 x - 4 ) - 3 ( x + 1 ) ^{2}}{( 3 x - 4 ) ^{2}}

Expand

2 (x + 1) (3 x - 4) - 3 (x + 1)^{2} : 3 x^{2} - 8 x - 11

= \frac{3 x ^{2} - 8 x - 11}{( 3 x - 4 ) ^{2}}

\int \frac{4}{x - 6} d x

3 x y^{^{'}} - 3 y = x^{- 7}

\frac{d}{d x} (x^{3} - 5 a x^{2} + 3 a^{2} x + b)

\int \frac{1}{u ^{2} - 1} d u

\int_{π}^{0} sin (x) d x

What is the derivative of ((x+1^2)/(3x-4)) ?
The derivative of ((x+1^2)/(3x-4)) is (3x^2-8x-11)/((3x-4)^2)
What is the first derivative of ((x+1^2)/(3x-4)) ?
The first derivative of ((x+1^2)/(3x-4)) is (3x^2-8x-11)/((3x-4)^2)