What is the derivative of f(x)= 3/(\sqrt[3]{x)} ?

The derivative of f(x)= 3/(\sqrt[3]{x)} is -1/(x^{4/3)}

What is the first derivative of f(x)= 3/(\sqrt[3]{x)} ?

The first derivative of f(x)= 3/(\sqrt[3]{x)} is -1/(x^{4/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

- \frac{1}{x ^{\frac{4}{3}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} (x^{- \frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- \frac{1}{3} x^{- \frac{1}{3} - 1})

Simplify

3 (- \frac{1}{3} x^{- \frac{1}{3} - 1}) : - \frac{1}{x ^{\frac{4}{3}}}

= - \frac{1}{x ^{\frac{4}{3}}}

y = x^{3}, (- 2, - 8)

n = 1 \sum \infty \frac{( - 3 ) ^{n}}{n}

\frac{d}{d x} (x - x^{- 1})

y^{^{'}} - \frac{3}{x} y = \frac{y ^{4}}{x ^{2}}

\frac{d}{d s} (s i)

What is the derivative of f(x)= 3/(\sqrt[3]{x)} ?
The derivative of f(x)= 3/(\sqrt[3]{x)} is -1/(x^{4/3)}
What is the first derivative of f(x)= 3/(\sqrt[3]{x)} ?
The first derivative of f(x)= 3/(\sqrt[3]{x)} is -1/(x^{4/3)}