What is the first derivative of 3x+3 ?

The first derivative of 3x+3 is 3

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derivative of 3x+3

\frac{d}{d x} (3 x + 3)

3

Solution steps

\frac{d}{d x} (3 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (3)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (3) = 0

= 3 + 0

Simplify

= 3

x \to 0 lim (\frac{x}{sin ( \frac{x}{4} )})

\frac{d}{d x} (e^{x} - 2 - x)

y^{^{'}} - \frac{9}{x} y = \frac{y ^{4}}{x ^{13}}, y (1) = 1

\frac{d x}{d t} - 4 x = cos (3 t), x (0) = - 1