What is the solution for y^'-9/x y=(y^4)/(x^{13)},y(1)=1 ?

The solution for y^'-9/x y=(y^4)/(x^{13)},y(1)=1 is y=(\sqrt[3]{5}x^9)/(\sqrt[3]{-x^{15)+6}}

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y^'-9/x y=(y^4)/(x^{13)},y(1)=1

y^{^{'}} - \frac{9}{x} y = \frac{y ^{4}}{x ^{13}}, y (1) = 1

Solution steps

y^{'} (x) - \frac{9}{x} y = \frac{y ^{4}}{x ^{13}}

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What is the solution for y^'-9/x y=(y^4)/(x^{13)},y(1)=1 ?
The solution for y^'-9/x y=(y^4)/(x^{13)},y(1)=1 is y=(\sqrt[3]{5}x^9)/(\sqrt[3]{-x^{15)+6}}