What is the limit as t approaches pi of-8sin(t/2) ?

The limit as t approaches pi of-8sin(t/2) is -8

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limit as t approaches pi of-8sin(t/2)

t \to π lim (- 8 sin (\frac{t}{2}))

- 8

Solution steps

t \to π lim (- 8 sin (\frac{t}{2}))

Plug in the value

t = π

= - 8 sin (\frac{π}{2})

Simplify

- 8 sin (\frac{π}{2}) : - 8

= - 8

\frac{\partial}{\partial y} (x^{a} y^{b})

\int_{0}^{π} sec^{2} (x) d x

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What is the limit as t approaches pi of-8sin(t/2) ?
The limit as t approaches pi of-8sin(t/2) is -8