What is the integral from 0 to pi of sec^2(x) ?

The integral from 0 to pi of sec^2(x) is diverges

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integral from 0 to pi of sec^2(x)

\int_{0}^{π} sec^{2} (x) d x

diverges

Solution steps

\int_{0}^{π} sec^{2} (x) d x

Take the denominator(s) of

sec^{2} (x)

and compare to zero:

x = \frac{π}{2}

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{\frac{π}{2}} sec^{2} (x) d x + \int_{\frac{π}{2}}^{π} sec^{2} (x) d x

\int_{0}^{\frac{π}{2}} sec^{2} (x) d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

c y^{- 4}

\int (3 x^{\frac{1}{3}}) d x

\int (e^{3 x + 9} - 3 x^{2}) d x

y = 8 arcsin (\frac{x}{4}) - \frac{x 16 - x ^{2}}{2}

\frac{\partial}{\partial x} (e^{y} cos (x))

What is the integral from 0 to pi of sec^2(x) ?
The integral from 0 to pi of sec^2(x) is diverges