What is (\partial)/(\partial x)(e^ycos(x)) ?

The answer to (\partial)/(\partial x)(e^ycos(x)) is -e^ysin(x)

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(\partial)/(\partial x)(e^ycos(x))

\frac{\partial}{\partial x} (e^{y} cos (x))

- e^{y} sin (x)

Solution steps

\frac{\partial}{\partial x} (e^{y} cos (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{y} \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= e^{y} (- sin (x))

Simplify

= - e^{y} sin (x)

\int_{- 1}^{1} 9 x^{2} + 6 x - 3 d x

\frac{\partial}{\partial x} (3 x^{2} - 3 y)

\frac{d}{d x} (\frac{1}{1 + x + x ^{2}})

(- x^{2})^{^{'}}

\frac{d}{d x} (x e^{x + 1})

What is (\partial)/(\partial x)(e^ycos(x)) ?
The answer to (\partial)/(\partial x)(e^ycos(x)) is -e^ysin(x)