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Popular >

integral from-1 to 1 of 9x^2+6x-3

Solution

\int_{- 1}^{1} 9 x^{2} + 6 x - 3 d x

Solution

0

Solution steps

\int_{- 1}^{1} 9 x^{2} + 6 x - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 9 x^{2} d x + \int_{- 1}^{1} 6 x d x - \int_{- 1}^{1} 3 d x

\int_{- 1}^{1} 9 x^{2} d x = 6

\int_{- 1}^{1} 6 x d x = 0

\int_{- 1}^{1} 3 d x = 6

= 6 + 0 - 6

Simplify

= 0

Popular Examples

(\partial)/(\partial x)(3x^2-3y)

\frac{\partial}{\partial x} (3 x^{2} - 3 y)

derivative of 1/(1+x+x^2)

\frac{d}{d x} (\frac{1}{1 + x + x ^{2}})

(- x^{2})^{^{'}}

derivative of xe^{x+1}

\frac{d}{d x} (x e^{x + 1})

(2+x)(dy)/(dx)=3y

(2 + x) \frac{d y}{d x} = 3 y

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of 9x^2+6x-3 ?
The integral from-1 to 1 of 9x^2+6x-3 is 0