What is the solution for derivative of sqrt(x)+sqrt(y)=2 ?

The solution for derivative of sqrt(x)+sqrt(y)=2 is y=4c_{1}x+4x^2-4xsqrt(x)-2c_{1}sqrt(x)+x+c_{1}^2

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derivative of sqrt(x)+sqrt(y)=2

\frac{d}{d x} (x + y) = 2

y = 4 c_{1} x + 4 x^{2} - 4 x x - 2 c_{1} x + x + c_{1}^{2}

Solution steps

\frac{d}{d x} (x + y) = 2

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

x + y = \int 2 d x

\int 2 d x = 2 x + c_{1}

x + y = 2 x + c_{1}

Isolate

y : y = 4 c_{1} x + 4 x^{2} - 4 x x - 2 c_{1} x + x + c_{1}^{2}

y = 4 c_{1} x + 4 x^{2} - 4 x x - 2 c_{1} x + x + c_{1}^{2}

8 t^{2} + 9

\int x^{2} e^{1 x} d x

\int \frac{e ^{x} + e ^{2 x}}{e ^{x}} d x

e^{- 2 t} sin (t)

x \to a lim (\frac{3}{0})

What is the solution for derivative of sqrt(x)+sqrt(y)=2 ?
The solution for derivative of sqrt(x)+sqrt(y)=2 is y=4c_{1}x+4x^2-4xsqrt(x)-2c_{1}sqrt(x)+x+c_{1}^2