What is the derivative of t^{-2} ?

The derivative of t^{-2} is -2/(t^3)

What is the first derivative of t^{-2} ?

The first derivative of t^{-2} is -2/(t^3)

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derivative of

t^{- 2}

- \frac{2}{t ^{3}}

Solution steps

\frac{d}{d t} (t^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 t^{- 2 - 1}

Simplify

- 2 t^{- 2 - 1} : - \frac{2}{t ^{3}}

= - \frac{2}{t ^{3}}

n = 0 \sum \infty \frac{1}{7 ^{n}}

\frac{d y}{d x} = \frac{( x + sec ^{2} ( x ) )}{y}

\int \frac{1}{1 + e ^{a x}} d x

\int \frac{x}{x ^{4} + 16} d x

2 y^{^{'''}} - 3 y^{^{''}} - 18 y^{^{'}} - 8 y = 0

What is the derivative of t^{-2} ?
The derivative of t^{-2} is -2/(t^3)
What is the first derivative of t^{-2} ?
The first derivative of t^{-2} is -2/(t^3)