What is the solution for (dy)/(dx)+y=x^2+1 ?

The solution for (dy)/(dx)+y=x^2+1 is y=x^2-2x+3+(c_{1})/(e^x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+y=x^2+1

\frac{d y}{d x} + y = x^{2} + 1

y = x^{2} - 2 x + 3 + \frac{c _{1}}{e ^{x}}

Solution steps

\frac{d y}{d x} + y = x^{2} + 1

Solve linear ODE:

y = x^{2} - 2 x + 3 + \frac{c _{1}}{e ^{x}}

y = x^{2} - 2 x + 3 + \frac{c _{1}}{e ^{x}}

\frac{\partial}{\partial x} (y^{2} - cos (x y))

\frac{d y}{d x} y = (3 x - 2 x^{2})^{3}

f (x) = \frac{x ^{2}}{( 3 + x )}

e^{\frac{1}{6} x^{6}}, 0

x \to - 6 - lim (- \frac{1}{x + 6})

What is the solution for (dy)/(dx)+y=x^2+1 ?
The solution for (dy)/(dx)+y=x^2+1 is y=x^2-2x+3+(c_{1})/(e^x)