What is the solution for y^{''}+3y=-9 ?

The solution for y^{''}+3y=-9 is y=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)-3

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y^{''}+3y=-9

y^{^{''}} + 3 y = - 9

y = c_{1} cos (3 t) + c_{2} sin (3 t) - 3

Solution steps

y^{''} (t) + 3 y = - 9

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t) - 3

y = c_{1} cos (3 t) + c_{2} sin (3 t) - 3

- 2 cot (x) csc (x)

x \to 2 π lim (\frac{1}{sin ( x )})

sin (2 x)

\frac{d}{d x} (\frac{x ^{4} - 4 x + 3}{x + 1})

(y)^{^{'}}

What is the solution for y^{''}+3y=-9 ?
The solution for y^{''}+3y=-9 is y=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)-3