What is the derivative of f(x)=ln(ln(x^2)) ?

The derivative of f(x)=ln(ln(x^2)) is 2/(xln(x^2))

What is the first derivative of f(x)=ln(ln(x^2)) ?

The first derivative of f(x)=ln(ln(x^2)) is 2/(xln(x^2))

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derivative of

f (x) = ln (ln (x^{2}))

\frac{2}{x ln ( x ^{2} )}

Solution steps

\frac{d}{d x} (ln (ln (x^{2})))

Apply the chain rule:

\frac{1}{ln ( x ^{2} )} \frac{d}{d x} (ln (x^{2}))

= \frac{1}{ln ( x ^{2} )} \frac{d}{d x} (ln (x^{2}))

\frac{d}{d x} (ln (x^{2})) = \frac{2}{x}

= \frac{1}{ln ( x ^{2} )} \cdot \frac{2}{x}

Simplify

\frac{1}{ln ( x ^{2} )} \cdot \frac{2}{x} : \frac{2}{x ln ( x ^{2} )}

= \frac{2}{x ln ( x ^{2} )}

x \to 1 lim (∣ 2 x ∣)

\frac{d y}{d x}, x + y^{2} = 1

x \to 0 - lim (3)

\frac{d}{d θ} (8 cos (θ) - 6 sin (θ))

f (x) = \frac{( - 2 )}{x}

What is the derivative of f(x)=ln(ln(x^2)) ?
The derivative of f(x)=ln(ln(x^2)) is 2/(xln(x^2))
What is the first derivative of f(x)=ln(ln(x^2)) ?
The first derivative of f(x)=ln(ln(x^2)) is 2/(xln(x^2))