What is the d/(dθ)(8cos(θ)-6sin(θ)) ?

The d/(dθ)(8cos(θ)-6sin(θ)) is -8sin(θ)-6cos(θ)

What is the first d/(dθ)(8cos(θ)-6sin(θ)) ?

The first d/(dθ)(8cos(θ)-6sin(θ)) is -8sin(θ)-6cos(θ)

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\frac{d}{d θ} (8 cos (θ) - 6 sin (θ))

- 8 sin (θ) - 6 cos (θ)

Solution steps

\frac{d}{d θ} (8 cos (θ) - 6 sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (8 cos (θ)) - \frac{d}{d θ} (6 sin (θ))

\frac{d}{d θ} (8 cos (θ)) = - 8 sin (θ)

\frac{d}{d θ} (6 sin (θ)) = 6 cos (θ)

= - 8 sin (θ) - 6 cos (θ)

f (x) = \frac{( - 2 )}{x}

\frac{d}{d x} (4 x^{4} + 3 x^{2})

f (x) = 5 + x^{2}

\int_{0}^{\frac{1}{2}} t^{2} d t

\frac{\partial}{\partial x} (8 + e^{- x y} cos (y))

What is the d/(dθ)(8cos(θ)-6sin(θ)) ?
The d/(dθ)(8cos(θ)-6sin(θ)) is -8sin(θ)-6cos(θ)
What is the first d/(dθ)(8cos(θ)-6sin(θ)) ?
The first d/(dθ)(8cos(θ)-6sin(θ)) is -8sin(θ)-6cos(θ)