What is the integral from 1 to infinity of x^{-4/5} ?

The integral from 1 to infinity of x^{-4/5} is diverges

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integral from 1 to infinity of x^{-4/5}

\int_{1}^{\infty} x^{- \frac{4}{5}} d x

diverges

Solution steps

\int_{1}^{\infty} x^{- \frac{4}{5}} d x

Compute the indefinite integral:

\int x^{- \frac{4}{5}} d x = 5 x^{\frac{1}{5}} + C

Compute the boundaries:

\int_{1}^{\infty} x^{- \frac{4}{5}} d x =

diverges

= diverges

f^{^{'}} (x) = 6 x

f (x) = \frac{2}{3 x}

\frac{d}{d x} (\frac{3 x ^{2}}{x ^{2} - 4})

\frac{d y}{d x} = cos (x - y)

n = 0 \sum \infty \frac{n + 6}{6}

What is the integral from 1 to infinity of x^{-4/5} ?
The integral from 1 to infinity of x^{-4/5} is diverges