What is the integral of sec^7(x)tan(x) ?

The integral of sec^7(x)tan(x) is (sec^7(x))/7+C

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integral of sec^7(x)tan(x)

\int sec^{7} (x) tan (x) d x

\frac{sec ^{7} ( x )}{7} + C

Solution steps

\int sec^{7} (x) tan (x) d x

Apply u-substitution

: \int u^{6} d u

= \int u^{6} d u

Apply the Power Rule

: \frac{u ^{7}}{7}

= \frac{u ^{7}}{7}

Substitute back

u = sec (x)

= \frac{sec ^{7} ( x )}{7}

Add a constant to the solution

= \frac{sec ^{7} ( x )}{7} + C

\int e^{t a n (v)} sec^{2} (v) d v

\frac{d}{d x} ((e^{- t^{2}}) x^{2})

\int \frac{x e ^{x^{2}}}{e ^{x^{2}} + 2} d x

n \to \infty + lim (1^{n})

x \to - 2 lim (\frac{x ^{3} - 1}{x - 1})

What is the integral of sec^7(x)tan(x) ?
The integral of sec^7(x)tan(x) is (sec^7(x))/7+C