What is the integral of e^{tan(v)}sec^2(v) ?

The integral of e^{tan(v)}sec^2(v) is e^{tan(v)}+C

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integral of e^{tan(v)}sec^2(v)

\int e^{t a n (v)} sec^{2} (v) d v

e^{t a n (v)} + C

Solution steps

\int e^{t a n (v)} sec^{2} (v) d v

Apply u-substitution

: \int e^{u} d u

= \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e^{u}

Substitute back

u = tan (v)

= e^{t a n (v)}

Add a constant to the solution

= e^{t a n (v)} + C

\frac{d}{d x} ((e^{- t^{2}}) x^{2})

\int \frac{x e ^{x^{2}}}{e ^{x^{2}} + 2} d x

n \to \infty + lim (1^{n})

x \to - 2 lim (\frac{x ^{3} - 1}{x - 1})

y^{^{''}} + 8 y + 16 y = 0

What is the integral of e^{tan(v)}sec^2(v) ?
The integral of e^{tan(v)}sec^2(v) is e^{tan(v)}+C