What is the derivative of ln(8-4x) ?

The derivative of ln(8-4x) is -1/(2-x)

What is the first derivative of ln(8-4x) ?

The first derivative of ln(8-4x) is -1/(2-x)

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\frac{d}{d x} (ln (8 - 4 x))

- \frac{1}{2 - x}

Solution steps

\frac{d}{d x} (ln (8 - 4 x))

Apply the chain rule:

\frac{1}{8 - 4 x} \frac{d}{d x} (8 - 4 x)

= \frac{1}{8 - 4 x} \frac{d}{d x} (8 - 4 x)

\frac{d}{d x} (8 - 4 x) = - 4

= \frac{1}{8 - 4 x} (- 4)

Simplify

\frac{1}{8 - 4 x} (- 4) : - \frac{1}{2 - x}

= - \frac{1}{2 - x}

\frac{d}{d x} (cos (x + e^{x}))

\frac{d}{d x} (\frac{x ^{2} + 4}{5 x - 9})

y^{^{''}} - 4 y^{^{'}} + 3 y = 0, y (0) = - 7.5, y^{^{'}} (0) = \frac{23}{5}

f (x) = 3

x \to 9 - lim (\frac{2}{x - 9})

What is the derivative of ln(8-4x) ?
The derivative of ln(8-4x) is -1/(2-x)
What is the first derivative of ln(8-4x) ?
The first derivative of ln(8-4x) is -1/(2-x)