What is the solution for y^{''}-4y^'+3y=0,y(0)=-7.5,y^'(0)= 23/5 ?

The solution for y^{''}-4y^'+3y=0,y(0)=-7.5,y^'(0)= 23/5 is y=6.05e^{3t}-13.55e^t

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y^{''}-4y^'+3y=0,y(0)=-7.5,y^'(0)= 23/5

y^{^{''}} - 4 y^{^{'}} + 3 y = 0, y (0) = - 7.5, y^{^{'}} (0) = \frac{23}{5}

y = 6.05 e^{3 t} - 13.55 e^{t}

Solution steps

y^{''} (t) - 4 y^{'} (t) + 3 y = 0

Solve linear ODE:

y = 6.05 e^{3 t} - 13.55 e^{t}

y = 6.05 e^{3 t} - 13.55 e^{t}

f (x) = 3

x \to 9 - lim (\frac{2}{x - 9})

\int tan^{4} (8 x) d x

\int \frac{1}{v ^{2} + 1} d v

y = 1 - x - x^{2}

What is the solution for y^{''}-4y^'+3y=0,y(0)=-7.5,y^'(0)= 23/5 ?
The solution for y^{''}-4y^'+3y=0,y(0)=-7.5,y^'(0)= 23/5 is y=6.05e^{3t}-13.55e^t