What is the tangent of (2x)/(x^2-7) ?

The tangent of (2x)/(x^2-7) is y=(2(-a_{0}^2-7))/((a_{0)^2-7)^2}x+(4a_{0}^3)/(a_{0)^4-14a_{0}^2+49}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of (2x)/(x^2-7)

tangent of

\frac{2 x}{x ^{2} - 7}

y = \frac{2 ( - a _{0}^{2} - 7 )}{( a _{0}^{2} - 7 ) ^{2}} x + \frac{4 a _{0}^{3}}{a _{0}^{4} - 14 a _{0}^{2} + 49}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{2 a _{0}}{a _{0}^{2} - 7})

Find the slope of

y = \frac{2 x}{x ^{2} - 7} : \frac{d y}{d x} = \frac{2 ( - x ^{2} - 7 )}{( x ^{2} - 7 ) ^{2}}

Compute the slope of

y = \frac{2 x}{x ^{2} - 7}

x = a_{0} : m = \frac{2 ( - a _{0}^{2} - 7 )}{( a _{0}^{2} - 7 ) ^{2}}

Find the line with slope m=

\frac{2 ( - a _{0}^{2} - 7 )}{( a _{0}^{2} - 7 ) ^{2}}

and passing through

(a_{0}, \frac{2 a _{0}}{a _{0}^{2} - 7}) : y = \frac{2 ( - a _{0}^{2} - 7 )}{( a _{0}^{2} - 7 ) ^{2}} x + \frac{4 a _{0}^{3}}{a _{0}^{4} - 14 a _{0}^{2} + 49}

y = \frac{2 ( - a _{0}^{2} - 7 )}{( a _{0}^{2} - 7 ) ^{2}} x + \frac{4 a _{0}^{3}}{a _{0}^{4} - 14 a _{0}^{2} + 49}

y^{^{'}} + 6 y = 3

\frac{d}{d x} (cos (x) - cos (2 x))

f (x) = \frac{x}{x + 1}

\int 3 x^{2} - x^{3} d x

x \to 1 lim (x + 8)

What is the tangent of (2x)/(x^2-7) ?
The tangent of (2x)/(x^2-7) is y=(2(-a_{0}^2-7))/((a_{0)^2-7)^2}x+(4a_{0}^3)/(a_{0)^4-14a_{0}^2+49}