What is area x=4sqrt(y),x=0,y=4 ?

The answer to area x=4sqrt(y),x=0,y=4 is 128/3

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area x=4sqrt(y),x=0,y=4

area

x = 4 y, x = 0, y = 4

\frac{128}{3}

Decimal

42.66666 \dots

Solution steps

Isolate

y

for

x = 4 y : y = \frac{x ^{2}}{16} {x \geq 0}

Apply the area formula:

\int_{- 8}^{8} \frac{x ^{2}}{16} - 4 d x

Solve

\int_{- 8}^{8} \frac{x ^{2}}{16} - 4 d x : \frac{128}{3}

The area is:

= \frac{128}{3}

\frac{e ^{x}}{2 x ^{2}}

\frac{d}{d x} (\frac{x}{x - 1})

(x^{5} + 2 x) \cdot (x^{3} + x^{2} + x + 7)

\int e^{- x} \cdot cos (w x) d x

y^{^{''}} + y^{^{'}} + y = 0, y (0) = 1, y^{^{'}} (0) = - 1

What is area x=4sqrt(y),x=0,y=4 ?
The answer to area x=4sqrt(y),x=0,y=4 is 128/3