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Popular >

y^'+2y=10

Solution

y^{^{'}} + 2 y = 10

Solution

y = - e^{- 2 t - c_{1}} + 5

Solution steps

y^{'} (t) + 2 y = 10

Solve separable ODE:

y = - e^{- 2 t - c_{1}} + 5

y = - e^{- 2 t - c_{1}} + 5

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=10 ?
The solution for y^'+2y=10 is y=-e^{-2t-c_{1}}+5