What is area x^3-8x^2+12x,-x^3+8x^2-12x ?

The answer to area x^3-8x^2+12x,-x^3+8x^2-12x is 296/3

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area x^3-8x^2+12x,-x^3+8x^2-12x

area

x^{3} - 8 x^{2} + 12 x, - x^{3} + 8 x^{2} - 12 x

\frac{296}{3}

Decimal

98.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{6} x^{3} - 8 x^{2} + 12 x - (- x^{3} + 8 x^{2} - 12 x) d x

Solve

\int_{0}^{6} x^{3} - 8 x^{2} + 12 x - (- x^{3} + 8 x^{2} - 12 x) d x : \frac{296}{3}

The area is:

= \frac{296}{3}

y = \frac{7}{( 1 - x ^{2} ) ^{3}}

\frac{\partial}{\partial x} (\frac{1}{x ^{4}})

e^{x} (y - 1) d x + 2 (e^{x} + 4) d y = 0

x, 4

\frac{3}{x ^{4} + 7 x + 1}

What is area x^3-8x^2+12x,-x^3+8x^2-12x ?
The answer to area x^3-8x^2+12x,-x^3+8x^2-12x is 296/3