What is taylor sqrt(x),4 ?

The answer to taylor sqrt(x),4 is 2+1/4 (x-4)-1/64 (x-4)^2+1/512 (x-4)^3-5/16384 (x-4)^4+\ldots

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taylor sqrt(x),4

taylor

x, 4

2 + \frac{1}{4} (x - 4) - \frac{1}{64} (x - 4)^{2} + \frac{1}{512} (x - 4)^{3} - \frac{5}{16384} (x - 4)^{4} + \dots

Solution steps

Apply the Taylor Formula

= 2 + \frac{\frac{d}{d x} ( x ) ( 4 )}{1 !} (x - 4) + \frac{\frac{d ^{2}}{d x ^{2}} ( x ) ( 4 )}{2 !} (x - 4)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x ) ( 4 )}{3 !} (x - 4)^{3} + \dots

Evaluate Derivatives

= 2 + \frac{\frac{1}{4}}{1 !} (x - 4) + \frac{- \frac{1}{32}}{2 !} (x - 4)^{2} + \frac{\frac{3}{256}}{3 !} (x - 4)^{3} + \frac{- \frac{15}{2048}}{4 !} (x - 4)^{4} + \dots

Refine

= 2 + \frac{1}{4} (x - 4) - \frac{1}{64} (x - 4)^{2} + \frac{1}{512} (x - 4)^{3} - \frac{5}{16384} (x - 4)^{4} + \dots

\frac{3}{x ^{4} + 7 x + 1}

y^{^{'}} = 3 x y

\frac{7 + 2 x}{1 - 6 x}

\frac{x ^{2} - 6 x - 1}{( x - 3 ) ^{2}}

x \to 1 lim ([2 f (x) + g (x)])

What is taylor sqrt(x),4 ?
The answer to taylor sqrt(x),4 is 2+1/4 (x-4)-1/64 (x-4)^2+1/512 (x-4)^3-5/16384 (x-4)^4+\ldots