What is the derivative of 34(3p+1)^{-2/5} ?

The derivative of 34(3p+1)^{-2/5} is -(204)/(5(3p+1)^{7/5)}

What is the first derivative of 34(3p+1)^{-2/5} ?

The first derivative of 34(3p+1)^{-2/5} is -(204)/(5(3p+1)^{7/5)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

34 (3 p + 1)^{- \frac{2}{5}}

- \frac{204}{5 ( 3 p + 1 ) ^{\frac{7}{5}}}

Solution steps

\frac{d}{d p} (34 (3 p + 1)^{- \frac{2}{5}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 34 \frac{d}{d p} ((3 p + 1)^{- \frac{2}{5}})

Apply the chain rule:

- \frac{2}{5 ( 3 p + 1 ) ^{\frac{7}{5}}} \frac{d}{d p} (3 p + 1)

= - \frac{2}{5 ( 3 p + 1 ) ^{\frac{7}{5}}} \frac{d}{d p} (3 p + 1)

\frac{d}{d p} (3 p + 1) = 3

= 34 (- \frac{2}{5 ( 3 p + 1 ) ^{\frac{7}{5}}} \cdot 3)

Simplify

34 (- \frac{2}{5 ( 3 p + 1 ) ^{\frac{7}{5}}} \cdot 3) : - \frac{204}{5 ( 3 p + 1 ) ^{\frac{7}{5}}}

= - \frac{204}{5 ( 3 p + 1 ) ^{\frac{7}{5}}}

\int \frac{2 x}{x ^{2} + 1} d x

\frac{1}{s ( s ^{2} + 25 )}

y = 4 tan (x), at x = \frac{π}{3}

\frac{d}{d x} (\frac{h ( x )}{x}) x = 2

f (x) = \frac{1}{1 + x ^{2}}

What is the derivative of 34(3p+1)^{-2/5} ?
The derivative of 34(3p+1)^{-2/5} is -(204)/(5(3p+1)^{7/5)}
What is the first derivative of 34(3p+1)^{-2/5} ?
The first derivative of 34(3p+1)^{-2/5} is -(204)/(5(3p+1)^{7/5)}