en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

t*y^'+y=2t

Solution

t \cdot y^{^{'}} + y = 2 t

Solution

y = t + \frac{c _{1}}{t}

Solution steps

t \cdot y^{'} (t) + y = 2 t

Solve linear ODE:

y = t + \frac{c _{1}}{t}

y = t + \frac{c _{1}}{t}

Popular Examples

y^{''}+y^'+3y=0

y^{^{''}} + y^{^{'}} + 3 y = 0

x y^{^{'}} + (x + 1) y = x

derivative of f(x)=(2x^2-x+1)*(x^2+2x+3)derivative of

f (x) = (2 x^{2} - x + 1) \cdot (x^{2} + 2 x + 3)

integral of 1/((x-1)(x+4))

\int \frac{1}{( x - 1 ) ( x + 4 )} d x

derivative of x^2*arctan(x)derivative of

x^{2} \cdot arctan (x)

Frequently Asked Questions (FAQ)

What is the solution for t*y^'+y=2t ?
The solution for t*y^'+y=2t is y=t+(c_{1})/t