What is the solution for (dy)/(dx)=cot(1-2x^2) ?

The solution for (dy)/(dx)=cot(1-2x^2) is y=integral of cot(1-2x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=cot(1-2x^2)

\frac{d y}{d x} = cot (1 - 2 x^{2})

y = \int cot (1 - 2 x^{2}) d x

Solution steps

\frac{d y}{d x} = cot (1 - 2 x^{2})

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = cot (1 - 2 x^{2})

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int cot (1 - 2 x^{2}) d x

y = \int cot (1 - 2 x^{2}) d x

\int \frac{1}{z ^{3} z ^{2} - 64} d z

\int \frac{9}{x + 2} d x

x \to 4 - lim (\frac{3}{x - 4})

\frac{4 x}{x ^{2} + 6}

\int 9 sin^{2} (x) cos^{3} (x) d x

What is the solution for (dy)/(dx)=cot(1-2x^2) ?
The solution for (dy)/(dx)=cot(1-2x^2) is y=integral of cot(1-2x^2)